q^2-4q+5=2,96

Solution for q^2-4q+5=2,96 equation:

q^2-4q+5=2.96

We move all terms to the left:

q^2-4q+5-(2.96)=0

We add all the numbers together, and all the variables

q^2-4q+2.04=0

a = 1; b = -4; c = +2.04;
Δ = b2-4ac
Δ = -42-4·1·2.04
Δ = 7.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{7.84}}{2*1}=\frac{4-\sqrt{7.84}}{2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{7.84}}{2*1}=\frac{4+\sqrt{7.84}}{2}
$